CH3COONa —> CH3COO- + Na+ 0.1_______________0.1 CH3COOH –> CH3COO- + H+ 0.1-x__________0.1+x____x Ta có: Ka = x(0.1+x)/(0.1-x) = 1.7510^{-5} => x = 1.7510^{-5} => CmH+ = 1.75*10^{-5} =>Ph = 4.757
CH3COONa —> CH3COO- + Na+ 0.1_______________0.1 CH3COOH –> CH3COO- + H+ 0.1-x__________0.1+x____x Ta có: Ka = x(0.1+x)/(0.1-x) = 1.7510^{-5} => x = 1.7510^{-5} => CmH+ = 1.75*10^{-5} =>Ph = 4.757